Could probably do an elo system and sample pairs. E.g.
1. Set the elo of all CVs to 1000 elo
2. Randomly pair up CVs and compare. Winners gain elo, losers lose elo.
3. Repeat #2 for a few iterations, then remove bottom X% of CVs.
4. Repeat 2-3 until the amount of remaining CVs is small enough to do an exhaustive comparison.
I don't have a mathematical proof, but I suspect that this is a decent cost-effective approximation of comparing every pair (depending on the parameters)
This has also been extended to evening events (dinners, balls, parties) in student towns. There “dk” stands for double quarter, so for example 18dk means that an event starts at 18:30, but you may show up from 18:00. And the time between 18:00-18:30 is used for mingling.
I'm not great at stats so I don't understand this example. Wouldn't the sunlight affect both groups equally? How can an equal exposure to sunlight create a significant difference?
1. Set the elo of all CVs to 1000 elo
2. Randomly pair up CVs and compare. Winners gain elo, losers lose elo.
3. Repeat #2 for a few iterations, then remove bottom X% of CVs.
4. Repeat 2-3 until the amount of remaining CVs is small enough to do an exhaustive comparison.
I don't have a mathematical proof, but I suspect that this is a decent cost-effective approximation of comparing every pair (depending on the parameters)