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What you’ve suggested is not equivalent. The a is always taken without negation, and that’s not the case in your rendering.


Ah. "a±(b-c)" then.

The fact I made that mistake in the first place just makes me more convinced the original form is unnecessarily complex to parse.


You're too fixated on the example. It's obviously used in cases where you cannot group like that:

    (-b ± sqrt(b² - 4ac)) / 2a = 2c / (-b ∓ sqrt(b² - 4ac))




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